We have the following template working with a single value in the "Computers" column, such as "C01".
However, sometimes the Computers column contains more than one computer, such as:
and we want each one converted to a separate link. Some sort of a "for each" within the cell.
Any ideas on how to do this?
Got it working. Note that we replace all commas with semi-colons prior to processing with PQ, hence the use of the semi-color in the below code.
<tbody>
#foreach ($row in $result)
<tr>
#foreach ($key in $row.keySet())
#if ($key == "Computers")
<td>
#set ($computers = $row.get("Computers"))
#foreach($computer in $computers.split(";"))
<a href="https://mydomain.com/prefix-$computer">$computer</a>
#end
</td>
#else
<td>$row.get($key)</td>
#end
#end
</tr>
#end
</tbody>
The Apache Velocity Engine - User Guide was very helpful.
Online forums and learning are now in one easy-to-use experience.
By continuing, you accept the updated Community Terms of Use and acknowledge the Privacy Policy. Your public name, photo, and achievements may be publicly visible and available in search engines.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.