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How to query stories and their linked subtasks in one query?

IT Accounts
Contributor
August 3, 2016

How to filter stories and their linked subtasks in one JQL query? Is it possible?

2 answers

0 votes
Indy Sue October 20, 2020 edited

Solution... 3 filters required...

1. STORIES filter called '369_Stories':  

issuetype in (story, PTR) AND cf[13056] = SAMSS-369 ORDER BY Key

2. SUB-TASKS filter called '369_Subtasks':

issuefunction in subtasksof("filter = 369_Stories") OR issuetype in (Sub-task) AND issuefunction in linkedissuesof("key = SAMSS-369")

3. COMBINED STORIES & SUB-TASKS filter called '369':

filter in (369_Stories, 369_Subtasks)

0 votes
105349
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August 3, 2016

Hello!

This is just a quick query I threw together.  It returns Stories that have Sub-Tasks; and you can add the Sub-Tasks column to see the Sub-Tasks.

issueFunction IN hasSubtasks() AND issuetype = Story

I'll see if I can come up with one that returns Stories and Sub-Tasks together.

Thanks!

Steven F Behnke
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August 3, 2016

Sorry but it's just not possible without plugins. The technology just isn't there yet. wink

IT Accounts
Contributor
August 10, 2016

I've found solution:

project = "ProjName" AND ( status in ("To Do", "In Progress", Done) AND type = sub-task AND issueFunction in subtasksOf("status in ('StoryStatus1','StoryStatus2','StoryStatus3')") OR status in ('StoryStatus1','StoryStatus2','StoryStatus3') AND issuetype = Story ) ORDER BY RANK ASC

Like • Rocky Y likes this

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